When a resistor is connected across the terminals of an ac generator (119 V) tha

Question

When a resistor is connected across the terminals of an ac generator (119 V) that has a fixed frequency, there is a current of 0.547 A in the resistor. When an inductor is connected across the terminals of the same generator, there is a current of 0.593 A in the inductor. When both the resistor and the inductor are connected in series between the terminals of this generator, what is (a) the impedance of the series combination and (b) the phase angle between the current and the voltage of the generator? Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.

Explanation / Answer

R=v/I = 119 /0.547 =217.5 ohm

XL = w*L = 119/0.593 =200.67 ohm

impedance of series = sqrt(R^2 +XL^2)= 295.93 ohm

b)phase angle between current and V =tan inverse (XL/R)=42.69 deg

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.