Two blocks of masses m1 = 2.00 kg and m2 = 3.90 kg are each released from rest a

Question

Two blocks of masses m1 = 2.00 kg and m2 = 3.90 kg are each released from rest at a height of h = 4.80 m on a frictionless track, as shown in the figure below, and undergo an elastic head-on collision. (Let the positive direction point to the right. Indicate the direction with the sign of your answer.) Determine the velocity of each block just before the collision. v1i = m/s v2i = m/s Determine the velocity of each block immediately after the collision. v1f = v2f = m/s Determine the maximum heights to which m1 and m2 rise after the collision. y1f = y2f = m

Explanation / Answer

v1f = (2 m2 v2 + (m1 - m2) v1)/(m1+m2)= (2*3.9*-9.7 + (2-3.9)*9.7)/(2+3.9)=-15.95 m/s
v2f = (2 m1 v1 + (m2 - m1) v2)/(m1+m2)= (2*2*9.7 + (3.9-2)*-9.7)/(2+3.9)=3.45 m/s

c)
1/2 mv ^2 = m g h
h = v^2/2g
y1f = 15.95^2/(2*9.81)=12.97 m

y2f = 3.45^2/(2*9.81)=0.607 m

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