A bullet with mass m = 5:21 g is moving horizontally with a speed v = 498 m/s wh
ID: 2237373 • Letter: A
Question
A bullet with mass m = 5:21 g is moving horizontally with a speed v = 498 m/s when it strikes a block of wood with mass M = 14.8 kg (initially at rest). The bullet embeds itself in the block. (a) What is the speed (m/s) of the bullet-block combination immediately after the collision? (b) What is the impulse (kg m/s) exerted on the block? (c) What is the nal kinetic energy (J) of the block? (d) How much work (J) did the bullet do on the block? (e) What was the change in kinetic energy (J) of the bullet? (f) How much work (J) was done on the bullet?Explanation / Answer
(a) mv = (m+M)(v1)
velocity = 0.175 m/s
(b) impulse = change in momentum = 2.59
(c) Kinetic energy = 0.226 J
(d) work done by bullet = change in KE of bullet = 646 J
(e) 646 J
(f) 645.77
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