A dancer is standing on one leg on a drawbridge that is about to open. The coeff

Question

A dancer is standing on one leg on a drawbridge that is about to open. The coefficients of static and kinetic friction between the drawbridge and the dancer's foot are Ug and Uk, respectively. n represents the normal force exerted on the dancer by the bridge, and Fg represents the gravitational force exerted on the dancer. The bridge starts to come back down again. The dancer stops sliding. However, again because of the age and design of the bridge it never makes it all the way down; rather it stops half a meter short. This half a meter corresponds to an angle theta <<1 degree (see the diagram, which has the angle exaggerated). What is the force of friction Ff now?

Explanation / Answer

The answers to thesequestions are much much simpler than what he has. He didnt read theproblem very carefully: Part A: zero. Heis right about that one. There is no friction force in part A Part B: f = n?s Friction force is ALWAYS the coefficient timesthe normal force. Part C: f = n?k Part Cis the same idea as part B but in part C he is sliding so we usethe coeff of kinetic friction.

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