The critical angle for a material in air is 52.3. (a) What is the refracted angl

Question

The critical angle for a material in air is 52.3. (a) What is the refracted angle for a light ray that enters the material from air with an incident angle of 25.0? (b) What is the refracted angle if the ray enters the material from methanol at 25? I used snell's law to get nb (index of refraction for the material) and then plugged it into the formula to get critical angle. arcsin(n2/n1). I was getting 32.28 but the answer is supposed to be 19.5. If anyone can explain what I am missing it would be much appreciated.

Explanation / Answer

n1 = 1 for air

n2*sin52.3 = n1*1 = 1*1

n2 = 1.263 (refractive index of material)

1*sin25 = 1.263*sin(theta)

(theta) = 19.5 degree

b)

RI of methanol = 1.32

1.32*sin25 = 1.263*sin(r)

sin(r) = .4416

= 26.21 degree

check definition of critical angle

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