The batteries in the circuit in the figure below have negligible internal resist

Question

The batteries in the circuit in the figure below have negligible internal resistance.  (Use the following as necessary: V = 21 V and R = 3 ?.)

    (a) Find the current using Kirchhoff's loop rule.
          A
    
    (b) Find the power delivered to or supplied by each battery.
    

    (c) Find the rate of Joule heating in each resistor.
             

21      W     
6      W     
The batteries in the circuit in the figure below have negligible internal resistance. (Use the following as necessary: V = 21 V and R = 3 ?.)

Explanation / Answer

Applying Kirchoff's loop law , (assuming a clockwise current i)
6+2i-21+3i = 0
5i = 15
i=3 A
So current in the circuit is 3 A clockwise
Current is coming out of 21 V battery (positive terminal ), So itis delivering power = VI = 21*3 = 63 W

Also Current is going into 6 V battery (positive terminal ),So it is consuming power = VI = 6*3 = 18 W

c)Power in 2 ? resistance =i2R = 9*2=18 W
Power in 3? resistance = i2R = 9*3=27 W
We can crosscheck than total power consumed =18+27+18 = 63 W =power input

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