A block of mass m = 9.00 k g is attached to the end of an ideal spring. Due to t

Question

A block of mass m= 9.00kg is attached to the end of an ideal spring. Due to the weight of the block, the block remains at rest when the spring is stretched a distance h= 7.00cm from its equilibrium length. The spring has an unknown spring constant k. Take the acceleration due to gravity to be g = 9.81

What is the spring constant K?

Suppose that the block gets bumped and undergoes a small vertical displacement. Find the resulting angular frequency ? of the block's oscillations about its equilibrium position.

A block of mass m= 9.00kg is attached to the end of an ideal spring. Due to the weight of the block, the block remains at rest when the spring is stretched a distance h= 7.00cm from its equilibrium length. The spring has an unknown spring constant k. Take the acceleration due to gravity to be g = 9.81 What is the spring constant K? Suppose that the block gets bumped and undergoes a small vertical displacement. Find the resulting angular frequency ? of the block's oscillations about its equilibrium position.

Explanation / Answer

Here

F = kx

Therfore

k = mg/x

= (9*9.81)/0.07

= 1261.285 N/m

w = sqrt(k/m)

= sqrt(1261.285/9)

= 11.838 rad/sec

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