In the circuit below, ? = 18.5 V, C 1 = 2.60 ?F, C 2 = 3.30 ?F, C 3 = 2.20 ?F, a
ID: 2241296 • Letter: I
Question
In the circuit below, ? = 18.5 V, C1 = 2.60 ?F, C2 = 3.30 ?F, C3 = 2.20 ?F, and C4 = 3.70 ?F.
When all capacitors are fully charged, what is
(a) the charge stored on capacitor 1?
?C
(b) the charge stored on capacitor 2?
?C
(c) the charge stored on capacitor 3?
?C
(d) the charge stored on capacitor 4?
?C
(e) the potential difference across the terminals of capacitor 2?
V
(f) the potential difference across the terminals of capacitor 3?
V
(g) the total charge stored (i.e. the charge stored if the capacitors were replaced by their equivalent capacitance; this is not the sum of your answers to parts a - d)?
?C
Explanation / Answer
? = 18.5 V, C1= 2.60 ?F, C2= 3.30 ?F, C3= 2.20 ?F, and C4= 3.70 ?F.
(a) the charge stored on capacitor 1?
Q=C1*V1
V1=E=18.5v beacuse E & C1 are in parallel
Q=2.60*18.5 = 48.1 uC
b) the charge stored on capacitor 2?
by voltage division V2= 18.5*2.2/(3.3+2.2) =7.4 V
Q=C2*V2 =3.3*7.4 =24.42 uC
c) the charge stored on capacitor 3?
by voltage division V3= 18.5*3.3/(3.3+2.2) =11.1 V
Q=C3*V3 =2.2*11.1 =24.42 uC
(d) the charge stored on capacitor 4?
V4=E=18.5v beacuse E & C4 are in parallel
Q=C4*V4 =3.7*18.5 =68.45 uC
e) the potential difference across the terminals of capacitor 2?
by voltage division V2= 18.5*2.2/(3.3+2.2) =7.4 V
f) the potential difference across the terminals of capacitor 3?
by voltage division V3= 18.5*3.3/(3.3+2.2) =11.1 V
(g) the total charge stored
Ceq = C1+C2C3/(C2+C3) + C4 = 2.6 + 3.3*2.2/(3.3+2.2) + 3.7 = 7.62 uF
Q= Ceq*E =7.62*18.5=140.97 uC
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