a) A mass m hanging from a spring with spring constant k is pulled down 4 cm and

Question

a) A mass m hanging from a spring with spring constant k is pulled down 4 cm and released, and oscillates with a frequency of 10 Hz. If this mass is doubled to 2m, what will the new frequency be?

b) If the mass is replaced with the original mass m, and the spring replaced with a spring having a spring constant of 4k, what will be the new frequency?

c) We replace the system with the original mass m and original spring with spring constant k. The mass is now pulled down 2 cm and released. What will the frequency be?

Explanation / Answer

a. f= 1/2pi (sqrt (k/m)

f1/f2 = sqrt(m2/m1)

f2 = f1* sqrt(1/2)

f2 = f1 *m

f2 = 7.07 Hz

b. f1/f2 = sqrt (4/1)

f2 = f1/2 = 10/2 = 5Hz

c. reamins same of 10 Hz

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