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ID: 2242462 • Letter: H
Question
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1.What is the magnetic flux through the loop shown in the figure below? ______________Wb
Express your answer using two significant figures.
2. A 22cm length of 0.29mm diameter nichrome wire is welded into a circular loop. The loop is placed between the poles of an electromagnet, and a field of 0.59T is switched on in a time of 14ms .
What is the induced current in the loop?
Express your answer to two significant figures and include the appropriate units.
3. What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 50V/m ?_______________________T
Express your answer using two significant figures.
What is the magnetic flux through the loop shown in the figure below? Wb Express your answer using two significant figures. A 22cm length of 0.29mm diameter nichrome wire is welded into a circular loop. The loop is placed between the poles of an electromagnet, and a field of 0.59T is switched on in a time of 14ms . What is the induced current in the loop? Express your answer to two significant figures and include the appropriate units. What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 50V/m ? Express your answer using two significant figures.Explanation / Answer
magnetic flux =B.A (here both B & A are vectors and dot product is taken )
=-2*0.2^2 + 1*0.2^2
= -0.04Wb
Area of loop=pie*r^2 { 2*pie*r=22 cm}; r=3.5 cm
=pie*3.5^2 =38.46 cm^2
induced emf = d(magnetic flux)/dt
= 0.3846*0.59/(14*10^(-3))
=16.07 V
resistance of wire= resistivity*lenth/area
=(1.5*10^-6)*0.22/(pie*((0.29*10^-3)/2)^2)
=5 ohm
induced current =induced emf/resistance of wire
=16.07/5 = 3.214 A
magnetic field amplitude = electric field/c
=50/(3*10^8) = 1.67*10^-7 T
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