The figure ( Figure 1 ) shows a model of a crane that may be mounted on a truck.

Question

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 95.00kg and length L= 6.000m is supported by two vertical massless strings. String A is attached at a distance d = 1.400m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 2000kg is supported by the crane at a distance x = 5.800m from the left end of the bar.

Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.

Find Tension in string A and in B?

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 95.00kg and length L= 6.000m is supported by two vertical massless strings. String A is attached at a distance d = 1.400m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 2000kg is supported by the crane at a distance x = 5.800m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity. Find Tension in string A and in B?

Explanation / Answer

Fnet = 0
Ta-Tb+m1*g+m2*g =0

Ta - Tb + 95*9.807 + 2000*9.807 = 0

Ta - Tb = 20545.665

net torque = 0

-Ta*d + m1*g*(L/2) + m2*g*x = 0

Ta*1.4 = (95*9.807*3) + (2000*9.807*5.8)

Ta = 83254.425 N

Tb = 62708.76 N

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