Assume a transparent rod of diameter d = 1.50 u m has an index o f refractionof
ID: 2242571 • Letter: A
Question
Assume a transparent rod of diameter d = 1.50 um has an index of
refractionof 1.46. Determine the maximum angle q for which the light rays incident on the end of the rod in Figure P35.39 are subject to total internal reflection along the walls of the rod. Your answer defines the size of the cone of acceptance for the rod.
Explanation / Answer
let the refraction angle be "r"
now angle of incidence on the inside =90-r
angle of refraction =90 degrees (for total internal reflection)
==> sin(90 degrees)/sin(90-r) =1.46
==> cos(r) = 1/1.46
==> r = 46.77 degrees
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