Can someone please explain how you get s2, I thought I understood but I\'m confu

Question

Can someone please explain how you get  s2, I thought I understood but I'm confused as to how you combine the angles of the first and second.

Ex:s1=50*.5=25

S2=25*cos^2theta......but what do I use for theta...do I subtract 30-60 or add the,m or what...I am trying to figure it out and I'm absurdly frustrated.

The drawing shows three polarizer/analyzer pairs. The incident light beam for each pair is unpolarized and has the same average intensity of 50 W/m2. Find the average intensity of the transmitted beam for each of the three cases (A, B, and C) shown in the drawing. S2 = S2 = S2 = Can someone please explain how you get s2, I thought I understood but I'm confused as to how you combine the angles of the first and second. Ex:s1=50*.5=25 S2=25*cos^2theta.....

Explanation / Answer

When a unpolarized light passes through first polarizer intensity becomes half

and through the 2nd polarizer intensity becomes (cos(theta))^2 times

I1 = (Io/2)cos^2(30-30) = 25 watt/m^2

I2 = (Io/2)*cos^2(60+30) = 0 watt/m^2


I3 = (Io/2)*cos^2(60-30) = 25*cos^2(30) = 18.75 watt/m^2

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