A light ray is incident normally on a prism (see figure below). Find the angle (

Question

A light ray is incident normally on a prism (see figure below). Find the angle (relative to the normal) of the light ray transmitted back into air at the point where light first emerges from the prism. (The index of refraction of the prism is 1.5. Take ? = 56.1

A light ray is incident normally on a prism (see figure below). Find the angle (relative to the normal) of the light ray transmitted back into air at the point where light first emerges from the prism. (The index of refraction of the prism is 1.5. Take ? = 56.1 degree .)

Explanation / Answer

For part a) n1*sin?3= n2*sin?4 : sin?3= 30 degrees n1=1.923 (from book "Serway") and n2=1.33

then rearrange that for the point P for part but ?2 needs to be 90 for total internal reflection

So, b) n1*sin?1=n2sin90 oh yea ?1=60 due to the triangle relationships.

I hope this helps! I too am in physics and it can be tough=))

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.