A L 1 = 1.94 m long string of mass 11.0 g is attached to a L 2 = 2.82 m long str

Question

A L1= 1.94 m long string of mass 11.0 g is attached to a L2 = 2.82 mlong string of mass 30.0 g (see figure). The strings are under a tension of 105 N.

(a) How long will it take for a wave pulse to travel from point A to point C?

(b) How long will it take for reflected pulses to return to point A?

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A L1 = 1.94 m long string of mass 11.0 g is attached to a L2 = 2.82 mlong string of mass 30.0 g (see figure). The strings are under a tension of 105 N. How long will it take for a wave pulse to travel from point A to point C? How long will it take for reflected pulses to return to point A?

Explanation / Answer

v1= sqrt(T1/mu1)= sqrt(105*1.94/0.011)= 136.081 m/s

v2= sqrt(T2/mu2)= sqrt(105*2.81/0.03)=99.17 m/s

a) time taken for a wave pulse to travel from point A to point C= L1/v1 +L2/v2= 1.94/136.081 +2.82/99.17 = 0.0427 s

b) time taken for reflected pulses to return to point A =2*T1 = 2*0.0427=0.0854 s

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