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Jack was exposed to fast neutrons; he received a radiation dose of 120 rem on pa

ID: 2244915 • Letter: J

Question

Jack was exposed to fast neutrons; he received a radiation dose of 120 rem on part of his hand, affecting 30.0 grams of tissue. The relative biological effectiveness (RBE) of these neutrons is 11.0. Part A How much radiation did Jack receive? Part B What was the total energy of the radiation Jack received? In J Part C Suppose Jill received the same rad dosage, but from beta rays with an RBE of 1.10 instead of from neutrons. What is the value of the equivalent dose she received? In rem Please show work. Jack was exposed to fast neutrons; he received a radiation dose of 120 rem on part of his hand, affecting 30.0 grams of tissue. The relative biological effectiveness (RBE) of these neutrons is 11.0. Part A How much radiation did Jack receive? Part B What was the total energy of the radiation Jack received? In J Part C Suppose Jill received the same rad dosage, but from beta rays with an RBE of 1.10 instead of from neutrons. What is the value of the equivalent dose she received? In rem Please show work. Part A How much radiation did Jack receive? Part B What was the total energy of the radiation Jack received? In J Part C Suppose Jill received the same rad dosage, but from beta rays with an RBE of 1.10 instead of from neutrons. What is the value of the equivalent dose she received? In rem Please show work. Part B What was the total energy of the radiation Jack received? In J Part C Suppose Jill received the same rad dosage, but from beta rays with an RBE of 1.10 instead of from neutrons. What is the value of the equivalent dose she received? In rem Please show work. Part C Suppose Jill received the same rad dosage, but from beta rays with an RBE of 1.10 instead of from neutrons. What is the value of the equivalent dose she received? In rem Please show work.

Explanation / Answer

1. Deq=D*(RBE)
Deq=120 RBE=11
Therefore D=Deq/RBE=120/11=10.90 rad

2. 1 rad = .01 J/Kg
10.90(J/Kg)*.03Kg= .327J

3. Deq=10.90(rad) * 1.10
Deq = 11.99 rem