(a) Find the speed of flow in the lower section. (b) Find the speed of flow in t

Question

(a) Find the speed of flow in the lower section.

(b) Find the speed of flow in the upper section.

(c) Find the volume flow rate through the pipe.

Water moves through a constricted pipe in steady, ideal flow. At the lower point shown in the figure below, the pressure is 1.80 times 105 Pa and the pipe radius is 2.50 cm. At the higher point located at y = 2.50 m, the pressure is 1.21 times 105 Pa and the pipe radius is 1.30 cm Find the speed of flow in the lower section. Find the speed of flow in the upper section. Find the volume flow rate through the pipe.

Explanation / Answer

by using equation of continuity,

A1*V1=A2*v2

v2/v1=A1/A2

or

v2/v1=(r1/r2)^2

v2/v1=(2.5/1.3)^2

v2/v1=3.698

v2=3.698*v1

a)

by using bernoulli's therom

p1+1/2*rho*v1^2+rho*g*h1=p2+1/2*rho*v2^2+rho*g*h2

p1+1/2*rho*v1^2=p2+1/2*rho*v2^2+rho*g*h2

p1-p2=1/2*rho[(v2^2- v1^2)+2g(h2-h1)]

(1.8-1.2)*10^5=1/2*1000[(v2^2 - v1^2)+2*9.8(2.5)]

118=(3.698*v1)^2 -v1^2)+49

(3.698*v1)^2 -v1^2)=69

(v1)^2(13.675-1)=69

(v1)^2(12.675)=69

v1=sqrt(69/12.675)

v1=2.333 m/sec

b)

v2=3.698*v1

v2=8.628 m/sec

c)

volume flow rate=A2*v2

=pi*r2^2*v2

=3.14*0.013^2*8.628

=4.5785*10^-3 m^3/sec

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.