While running, a 72 k g student generates thermal energy at a rate of 1300 W . T

Question

While running, a 72kg  student generates thermal energy at a rate of 1300W . To maintain a constant body temperature of 36?C, this energy must be removed by perspiration or other mechanisms. Part A If these mechanisms failed and the heat could not flow out of the student's body, for what amount of time could a student run before irreversible body damage occurred? (Protein structures in the body are damaged irreversibly if the body temperature rises to 46?C or above. The specific heat capacity of a typical human body is 3480 J/(kg?K) slightly less than that of water. The difference is due to the presence of protein, fat, and minerals, which have lower specific heat capacities.) Express your answer using two significant figures.

Please thouroughly explain the setup process so I can make the connection for myself. I do not need you to solve it for me.
While running, a 72kg  student generates thermal energy at a rate of 1300W . To maintain a constant body temperature of 36?C, this energy must be removed by perspiration or other mechanisms. While running, a 72kg  student generates thermal energy at a rate of 1300W . To maintain a constant body temperature of 36?C, this energy must be removed by perspiration or other mechanisms. While running, a 72kg  student generates thermal energy at a rate of 1300W . To maintain a constant body temperature of 36?C, this energy must be removed by perspiration or other mechanisms. While running, a 72kg  student generates thermal energy at a rate of 1300W . To maintain a constant body temperature of 36?C, this energy must be removed by perspiration or other mechanisms. Part A If these mechanisms failed and the heat could not flow out of the student's body, for what amount of time could a student run before irreversible body damage occurred? (Protein structures in the body are damaged irreversibly if the body temperature rises to 46?C or above. The specific heat capacity of a typical human body is 3480 J/(kg?K) slightly less than that of water. The difference is due to the presence of protein, fat, and minerals, which have lower specific heat capacities.) Express your answer using two significant figures.

Please thouroughly explain the setup process so I can make the connection for myself. I do not need you to solve it for me.

Explanation / Answer

given energy rate= 1300

so energy = 1300*time

so or permissble energy is = mc(T2-T1)

m=72Kg

c=3480

T2-T1 = 46-36 = 10

so E = 2505600 J

so time = E/1300 =1927 seconds = 32.12 min

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