#include <stdio.h> #pragma warning(disable : 4996) // CSE 240 Fall 2017 Homework

Question

#include <stdio.h>
#pragma warning(disable : 4996)

// CSE 240 Fall 2017 Homework 1 Question 3 (25 points)
// Before starting this assignment, please compile and run this program.
// You will first notice that the program will not compile. Fix the errors and define the error types.
// Next, you will notice that the program is printing incorrect information. Fix the errors and define those error types.

void main() {

   // Problem 1: (4 points)
   // The statement below should cause the program to not compile. Correct the error(s). (2 points).

   y = 67

       printf("Integer y is equal to %d ", y);

   // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).
   // Your answer should be either Syntactic, Semantic, or Contextual.
   printf("Error Type: ________ ");

   // Problem 2: (4 points)
   // Half of 10 is 5, why is the program printing that half of 10 is 0? Correct the error(s) (2 points).

   int x = 10;

   printf("Half of %d is %d ", x, x * (1 / 2));

   // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).
   // Your answer should be either Syntactic, Semantic, or Contextual.
   printf("Error Type: ________ ");

//Problem 3 (2 points)
//Integer variable y is initialized to 67. However the print statement is giving a different result. Why is it giving that particular character as result?(1 point)
printf("%c",y);
// Your answer should be either Syntactic, Semantic, or Contextual. (1 point)
   printf("Error Type: ________ ");

//Give your explanation here:
printf("Explanation:_____________ ");

   // Problem 4: (2 points)
   // Float variable a has been initialized to 10.5, why does the program seem to think otherwise? Correct the error(s) (2 points).

   float a = 10.5;

   if (a = 20);
   printf("a is equal to 20. ");
   if (a > 20);
   printf("a is greater than 20. ");
   if (a < 20);
   printf("a is less than 20. ");

   // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).
   // Your answer should be either Syntactic, Semantic, or Contextual.
   printf("Error Type: ________ ");

   // Problem 5: (4 points)
   // Surely, 10 is an even number. Why is the program printing that 10 is an odd number? Correct the error(s) (2 points).

   x = 10;

   if (x / 2 == 0)
       printf("%d is an even number. ", x);
   if (x / 2 != 0)
       printf("%d is an odd number. ", x);

   // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).
   // Your answer should be either Syntactic, Semantic, or Contextual.
   printf("Error Type: ________ ");

   // Problem 6: (4 points)
   // This bit of code is meant to print "Hello World!". Correct the error(s) (2 points).

   printf("Hello %d ", "World!");

   // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).
   // Your answer should be either Syntactic, Semantic, or Contextual.
   printf("Error Type: ________ ");
}

3. You are given a file named "hw01q3.c". All instructions are given in the form of comments in the file. You are to correct the errors and identify which error type they are. Please read all instructions very carefully, then complete and submit the updated file. [20 points]

Explanation / Answer

Problem 1:

There is no semicolon after y = 67. Also y is not declared with a type.

The error type is a syntactic error.

Problem 2:

                                   

We are multiplying integer x with (1/2). Hence, when we multiply integer with any number, it is also converted to integer also. So,

                                    (1/2)=0.5 = 0(When converted to integer)

Therefore, x*0 = 0.

The error type is a semantic error.

Problem 3:

In the print statement, %c is used instead of %d to print an integer.

%c is used to print a charactor.Hence, 67 is converted to a character with ASCII code = 67.

The error type is a semantic error.

Problem 4:

There is semicolon after the if satements, so the if statement ends after the semicolon and the next printf statement is executed. Also in the first if statement use == sign instead of = sign to check for equality.

The error type is a semantic error.

Problem 5:

x / 2 = 5

Hence, the output is not as expected.

The error type is a semantic error.

Problem 6:

Instead of %d use %s in the printf statement as %d is used to print an integer as %s is used to print a string.

The error type is a semantic error.

Correct Code:

#include<stdio.h>

int main() {

    // Problem 1: (4 points)

    // The statement below should cause the program to not compile. Correct the error(s). (2 points).

    int y = 67;

        printf("Integer y is equal to %d ", y);

    // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).

    // Your answer should be either Syntactic, Semantic, or Contextual.

    printf("Error Type: Syntactic ");

    // Problem 2: (4 points)

    // Half of 10 is 5, why is the program printing that half of 10 is 0? Correct the error(s) (2 points).

    int x = 10;

    printf("Half of %d is %f ", x, x * 0.5);

    // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).

    // Your answer should be either Syntactic, Semantic, or Contextual.

    printf("Error Type: Semantic ");

     //Problem 3    (2 points)

     //Integer variable y is initialized to 67. However the print statement is giving a different result. Why is it giving that particular character as result?(1 point)

    printf("%d ",y);

    // Your answer should be either Syntactic, Semantic, or Contextual. (1 point)

    printf("Error Type: Semantic ");

    

     //Give your explanation here:

     printf("Explanation:In the print statement, %c is used instead of %d to print an integer.%c is used to print a charactor.Hence, 67 is converted to a character with ASCII code = 67. ");

    

    // Problem 4: (2 points)

    // Float variable a has been initialized to 10.5, why does the program seem to think otherwise? Correct the error(s) (2 points).

    float a = 10.5;

    if (a == 20)

    printf("a is equal to 20. ");

    if (a > 20)

    printf("a is greater than 20. ");

    if (a < 20)

    printf("a is less than 20. ");

    // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).

    // Your answer should be either Syntactic, Semantic, or Contextual.

    printf("Error Type: Semantic ");

    // Problem 5: (4 points)

    // Surely, 10 is an even number. Why is the program printing that 10 is an odd number? Correct the error(s) (2 points).

    x = 10;

    if (x % 2 == 0)

        printf("%d is an even number. ", x);

    if (x % 2 != 0)

        printf("%d is an odd number. ", x);

    // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).

    // Your answer should be either Syntactic, Semantic, or Contextual.

    printf("Error Type: Semantic ");

    // Problem 6: (4 points)

    // This bit of code is meant to print "Hello World!". Correct the error(s) (2 points).

    printf("Hello %s ", "World!");

    // Define what type of error this is, your answer should replace the space next to "Error Type: " below (2 points).

    // Your answer should be either Syntactic, Semantic, or Contextual.

    printf("Error Type: Semantic ");

}

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