Sensors A and B output voltages are 1.20V and 1.50V when there is no fluid flow,
ID: 2248206 • Letter: S
Question
Sensors A and B output voltages are 1.20V and 1.50V when there is no fluid flow, due partly to the tube not being level, and 1.38 V and 1.55 V for a flow rate of 200 ml per 80 seconds. Note: solid-state pressure sensors (Omega PX138-0.3D5V) and to calculate the experimental measurement of PAB(exp) we multiplying VAB by 1000 (this is the calibration factor for this model of pressure sensor).
a. What is the change in sensor A voltage?
b. What is the change in sensor B voltage?
c. Hence, calculate the pressure difference due to this flow rate in (a) units of V and (b) in units of Pa.
Overflow Upper Reservoir Pressure Valve Sensor A Pressure Sensor B Pipe Pump Lower ReservoirExplanation / Answer
a) change in sensor A voltage=1.38-1.20=.18V
b) change in sensor B voltage=1.55-1.5=.05V
c) pressure change= density*(square(v2)-square(v1))/2g
v2=1.55V in volts
V1=1.38V in volts
Pressure=1*.17*.17/(2*9.8)=.00294
v2=200/80 ml/sec=.0025 l/sec
V1=0
P=.0000003189 Pa
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