a uniformly distributed load feeder model of 10 equal loads. Total feeder load =

Question

a uniformly distributed load feeder model of 10 equal loads. Total feeder load = 100 kVA (3-phase), at peak, operating at 0.9 power factor agging. Total feeder length = 500 m. The cable impedance = 0.315 +j0.365 ohms/phase/kilometre. Use the residential load curve (refer Addendum)

Allow for embedded solar at each node.The solar sources are generators, so they will be represented by negative real power loads. Assume they will operate at unity power factor. Run the load flow for late afternoon peak load conditions, when embedded solar = 0.3 * peak load. Record your results. Comment on the improvement in feeder current and voltage drop. b) Now, run the load flow for residential midday light load conditions, when embedded solar = peak load value, but the midday load is 0.3 * peak load (i.e. embedded solar = 3 * midday load). Record your results. Comment on the feeder current and voltage drop. What happens to the voltage drop? What is the voltage spread at the end of the feeder (node #10) from midday to evening peak situations with solar present?

Explanation / Answer

set up Feeder Model.
a) Develop a radial load flow program and set up a uniformly distributed load feeder model of 10
equal loads. Total feeder load = 100 kVA (3-phase), at peak, operating at 0.9 power factor agging. Total feeder length = 500 m. The cable impedance = 0.315 +j0.365
ohms/phase/kilometre. Use the residential load curve (refer Addendum).
b) Run your load flow. Are current and voltage constraints being exceeded? Current constraint =
200 A/phase; voltage constraint = 415 V +/- 5%. If the supply end voltage was raised above 415
V would this solve any peak load?
c) Now, run the load flow for light-load conditions = 30% of peak load conditions (use residential

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