a) The circuit above is a combination of instrumentation amplifiers with cascade
ID: 2249310 • Letter: A
Question
a) The circuit above is a combination of instrumentation amplifiers with cascaded filters. Explain what the integrator does for this circuit
b) I buitl the circuit above and measured the outputs at VOut-Final, Vout-1 and VOut. I then reconfigure the arbitrary waveform generator to load the supplied file and measured the same outputs. I was wondering why the results differ and if the results at the outputs are expected
This is what I got after the first test: This is what I got after reconfiguring the arbitrary waveform
VOut-Final: 18.6 V VOut-Final: 16 V
Vout-1: 12.6V Vout-1: 5.43V
VOut: 8.52V VOut: 8.40V
This is a picture of the oscilloscope at VOut-Final
This is a picture of the oscilloscope at VOut-Final with arbitrary waveform reconfigured
C1 C3 0.002F VCC Vout- TLOTZACP UTA TLOT2ACP RS VOut-Fina SekO 56k0 56kO R3 47kO C4 R7 4TRO Ca VEE .002yF R4 82KO RB VCC Vie TLOT2ACP CS R9 R1368k0 6BkD VCC VEE Integrator U4A VOut VCC R15 22KO TLOTZACP V1 VEE R14 R11 R12Explanation / Answer
(a) The above given circuit uses the instrumentation amplifiers with combination of number of capacitors and resisitors to get the desired waveform as the output which is the amplified signal of input voltage.
To eliminate the disturbances and considering only the required output we are using the cascaded filters.
The Integrator used in the circuit serves the main purpose as a Totalizer, Because the signal coming from the two initial instrumentation amplifier should be considered.
The totalizer is a devices which totalizes or adds all the inputs given to the device. That action is performed by the integrator connected in the instrumentation amplifier circuit.
(b) As seen in the figure we took the reference of the signals for Vin and Vout-1 . In the first case the input voltage we set to 1.20volts and the frequency of the input is 142 hz. And hence the Vout-1 and Vin are in sinusoidal AC form with 142hz frequency. Input voltage is 1.20 v AC and the output amplified voltage is 18.6v in the 1st case
but when we reconfigure the arbitary waveform by adding the data file which is a DC level file, the frequency of the waveform is disturbed and the Vout-1 is disturbed which is shown in second case. And hence though there is a small change in input as 1.19V, the output is greatly reduced to 16V.
We can say that the output waveform and values are changed due to addition of data file which is a DC file which has no frequency.
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