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et Chrome File Edit View History Bookmarks People Window Help, 66% @T Tue Nov 21 9:34 AM a E As Hw11 due Tues Nov 21-EE- WeBWorK : JHeynssens_188:x C secure https://webwork.math.nau.edu/webwork2JHeynssens_188/Hw11-Fall-2017/3/ -13.0057+7.5i -13.00577.5000i correct At least one of the answers above is NOT correct. (15 points) his In the network in the figure with Val-13V@vi-70deg, VM2-15 V, 12-150deg, 4,-134. ,-160 deg, R1-1962, R-14f2 and Zc--i2, find Voin the circuit using source transformation. There are 3 sources that you could transform. Choosing Vw2 will result in losing the voltage across R2 Choosing I and R1 will result in a series voltage source-impedance combination in parallel with Vi and Zc which does not lead to a circuit simplification. VMi will result in a current source and impedance in parallel to a voltage source in series with an impedance to find VoBe careful of signs. Enter complex numbers as either a+bi, .e., 3+4i, or aeA (bi) where b is in radians, .e., 5eA(0.927). The transformation of Vi and Zc results in a current source (pointing up) of 11-1-1 2.2 1600+4.44i Combining Zc and RI in parallel is 29 = 0.0525-0.9972i Combining 11 and IM results in (pointing up) 13 = 0.0000 + 0.0063i The transformation of 13 and 2,3 results in a voltage source of V3 =-0.0062-0.0003i The final value Vo13.00577.5000iV Note: Yo u can earn partial credit on this problem. Preview My Answers Submit Answers

Explanation / Answer

Given data:-

VM1=13V

angle=70deg

converting it to complex form,we get

=4.446+12.216i

Zc=-i omega

Using these two datas,current I1 =((4.446+12.216i)/(-i))

=-12.216+4.446i A

As Zc and R1 are in parallel,Z3=(Zc*R1)/(Zc+R1)

=(-i*19)/(-i+19)=0.0525-0.9972i

Im=13A

angle=160deg

converting Im to complex form,we get

=-12.216+4.446i

Adding up I1 and Im,we get I3=-24.432+8.892i A(current can never be negative or 0A)

Using I3 and Z3,we calculate V3 as,

=(-24.432+8.892i)*(0.0525-0.9972i)=7.584+24.830i V

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