In the figure, light is incident perpendicularly on a thin layer of material 2 t

Question

In the figure, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) The waves of rays r1 and r2 interfere. The parameters for this problem are these: n1 = 1.50 , n2 = 1.64 , n3 = 1.36 , wavelength ? in air = 600 nm. What is the third least thickness that gives an interference maximum of rays r1 and r2? http://edugen.wileyplus.com/edugen/courses/crs4957/art/qb/qu/ch0/img1337328789019_7390223867688559.jpg

Explanation / Answer

2nt = (m + 0.5)(lambda)

For the third least thickness m = 2

2(1.64)(t) = (2.5)(600 * 10-9)

t = 4.57 * 10-7 m = 457 nm

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