Determine the rotational inertia of a ring on a turntable system in two ways sym
ID: 2251739 • Letter: D
Question
Determine the rotational inertia of a ring on a turntable system in two ways symbolically; (1) via force and torque analysis, and (2) via mass and dimension measurement using table (10.2) (The pulley is massless)
Given: mass in hanging object, radius of innerside of ring, radius of outerside of ring, radius of turntable spindle (rs), linear acceleration with the ring on the turntable, and linear acceleration without the ring on the turntable.
Having a hard time with this one.
table 10.2
Determine the rotational inertia of a ring on a turntable system in two ways symbolically; (1) via force and torque analysis, and (2) via mass and dimension measurement using table (10.2) (The pulley is massless)Explanation / Answer
1) Through force and torque analysis:
F = m*g
T = F*rs = m*g*rs
T =I(turntable)*alpha0 ,without the ring
T = (I(turntable)+I(ring))*alpha ,with the ring
alpha is the angular acceleration a = alpha*rs, a0=alpha0*rs
I(t)*alpah0 = (I(t)+I(r))*alpha
I(t) / (I(t)+I(r)) = alpha / alpha0
I(t)/ I(r) = alpha / (alpha0 -alpha)
i(t) / I(r) = a/ (a0-a)
I(r) = I(t) * (a0 -a)/a = I(t) *(a0/a -1)
Where the turntable moment of inertia is I(t) =M*R^2/2
if the mass of the turntable is M and radius of turntable is R.
or you know that
T =I(t)*a0/rs
I(t) = T*rs/a0 = m*g*rs*rs/a0 = m*g*rs^2/a0
Thus
I(r) = m*g*rs^2*(a0-a) / (a0*a)
2) Through computation
If you have z axis perpendicular to the plane of the ring, and x,y axis in the plane of the ring one can write
Iz = integral(r^2*dm) =integral(x^2+y^2)*dm = integral(x^2*dm) +integral(y^2*dm) =Ix+Iy
from symmetry you have Ix =Iy
and therefore
Iz =2Ix=2Iy
Now to determine Iz
Iz =integral (from R to r) (r^2*dm)
dm = sigma*dS =sigma*2*pi*r*dr , here sigma = M/S = M / [pi(R^2-r^2)], M is ring mass
Iz =integral(from R to r) (r^2*sigma*2*pi*r*dr) = (pi*sigma/2) (R^4 -r^4)= (M/2) (R^2+r^2)
Iz =(M/2) (R^2+r^2) r is outer radius, r is inner radious of ring
From tha table 10.2 it is the second option (I for cylinder or ring about central axis)
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