A mortar crew is positioned near the top of a steep hill. Enemy forces are charg

Question

A mortar crew is positioned near the top of a steep hill. Enemy forces are charging up the hill and it is necessary for the crew to spring into action. Angling the mortar at an angle of ? = 52.0o (as shown), the crew fires the shell at a muzzle velocity of 189 feet per second. How far down the hill does the shell strike if the hill subtends an angle ? = 35.0o from the horizontal? (Ignore air friction.)

How long will the mortar shell remain in the air?

How fast will the shell be traveling when it hits the ground?

Explanation / Answer

No diagram. Trajectory eqn:
y = h + x

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