As shown, a force vector with a magnitude of c= 44.0 is applied at point A and i

Question

As shown, a force vector with a magnitude of c= 44.0 is applied at point A and is directed toward point C. (Part A figure) The distance a is 7.50 and the distance b is 6.00 . What are the i, j, and k components of F?

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As shown, a force vector with a magnitude of c= 44.0 is applied at point A and is directed toward point C. The distance a is 7.50 and the distance b is 6.00 . What are the i, j, and k components of F?

Explanation / Answer

the force vector is c = 44.0 at (0,0)

the point a is (7.50,0)

the point b is (0,6.00)

the angle between a and c is

A = tan^-1(0 - 0/7.50 - 0) = 0o

the angle between b and c is

B = tan^-1(6.00 - 0/0 - 0) = 90o

the i component of F is Fx = 44.0 x cosA

the j component of F is Fy = 44.0 x sinB

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