A 46.5 kg block sits at rest on a frictionless, horizontal surface. It is connec

ID: 2252989 • Letter: A

Question

A 46.5 kg block sits at rest on a frictionless, horizontal surface. It is connected horizontally, via a massless, ideal spring to a stationary wall. A force is then used to displace and hold the block in a new position (so that the spring is compressed). Then the block is released to move freely. In that first instant of motion, its acceleration is 9.73 m/s2, and when it passes through its original (first) rest position, its speed is 18.2 m/s. What is the spring constant, k? A 46.5 kg block sits at rest on a frictionless, horizontal surface. It is connected horizontally, via a massless, ideal spring to a stationary wall. A force is then used to displace and hold the block in a new position (so that the spring is compressed). Then the block is released to move freely. In that first instant of motion, its acceleration is 9.73 m/s2, and when it passes through its original (first) rest position, its speed is 18.2 m/s. What is the spring constant, k? A 46.5 kg block sits at rest on a frictionless, horizontal surface. It is connected horizontally, via a massless, ideal spring to a stationary wall. A force is then used to displace and hold the block in a new position (so that the spring is compressed). Then the block is released to move freely. In that first instant of motion, its acceleration is 9.73 m/s2, and when it passes through its original (first) rest position, its speed is 18.2 m/s. What is the spring constant, k? A 46.5 kg block sits at rest on a frictionless, horizontal surface. It is connected horizontally, via a massless, ideal spring to a stationary wall. A force is then used to displace and hold the block in a new position (so that the spring is compressed). Then the block is released to move freely. In that first instant of motion, its acceleration is 9.73 m/s2, and when it passes through its original (first) rest position, its speed is 18.2 m/s. What is the spring constant, k?

Explanation / Answer

a=v/t

t=18.2/9.73

=1.87 sec

displacement x=vt=1.87*18.2

=34.04

F=ma=kx

46.5*9.73=k*34.04

k= 15KN

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A 46.5 kg block sits at rest on a frictionless, horizontal surface. It is connec

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