(67) The Mariana trench is located in the floor of the Pacific Ocean at a depth

Question

(67)The Mariana trench is located in the floor of the Pacific Ocean at a depth of about 11300 m below the surface of the water. The density of seawater is 1025 kg/m3.

(a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.14 m)?

A copper cube, 0.28 m on a side, is subjected to two shearing forces, each which has a magnitude F = 5.20 times 106 N (see the drawing). Find the angle ? (in degrees), which is one measure of how the shape of the block has been altered by shear deformation. The Mariana trench is located in the floor of the Pacific Ocean at a depth of about 11300 m below the surface of the water. The density of seawater is 1025 kg/m3. If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.14 m)? A water tower is a familiar sight in many towns. The purpose of such a tower is to provide storage capacity and to provide sufficient pressure in the pipes that deliver the water to customers. The drawing shows a spherical reservoir that contains 6.50 times 105 kg of water when full. (h = 7.50 m.) The reservoir is vented to the atmosphere at the top. For a full reservoir, find the gauge pressure that the water has at the faucet in each house. Ignore the diameter of the delivery pipes.

Explanation / Answer

Here is an answer to just one question, I chose the longest one and the most difficult one for you. Number 70.

Since you are only allowed to ask one question per post, I can only answer one question per post. Here is the solution for number 70...

Since the density of water is 1000 kg/m^3 and we have 6.50 X 10^5 kg of water in the sphere, we can find the diameter of the sphere.

Density = m/V

1000 = 6.50 X 10^5/V

V = 650 m^3

Volume of a sphere is 4/3pir^3

650 = 4/3(pi)(r^3)

r = 5.37 m

The diameter = 2r = 10.75 m

Thus the height of the water from the top of the tower to ground = 10.75 + 15 = 25.75 m

The pressure = pgh

At faucet A, Pressure = (1000)(9.8)(25.75) = 2.52 X 10^5 Pa

At faucet B, Pressure = (1000)(9.8)(25.75 - 7.5) = 1.79 X 10^5 Pa

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