The triangular coil of wire in the drawing is free to rotate about an axis that

Question

The triangular coil of wire in the drawing is free to rotate about an axis that is attached along side AC. The current in the loop is 4.94 A, and the magnetic field (parallel to the plane of the loop and side AB) is B = 1.7 T. (a) What is the magnetic moment of the loop, and (b) what is the magnitude of the net torque exerted on the loop by the magnetic field?

The triangular coil of wire in the drawing is free to rotate about an axis that is attached along side AC. The current in the loop is 4.94 A, and the magnetic field (parallel to the plane of the loop and side AB) is B = 1.7 T. (a) What is the magnetic moment of the loop, and (b) what is the magnitude of the net torque exerted on the loop by the magnetic field?

Explanation / Answer

For each side, F = IL X B, a vector cross product, and |F| = ILBsin?, where ? is the angle between IL and B.
To solve the problem, for each side use trig to get the length L and simple geometry to determine ?. Then plug the values into the equation.
Note ? = 0 for side AB so its force = 0. And the signs of the forces on AC and CB are opposite; one is into the page and one is out. I'll leave it to you to determine which is which; use the right-hand rule (ref.). And the magnitudes of the forces on AC and CB are equal (|BCsin?| = |AC|), so ... answer B = 0!

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