help A diffraction pattern is formed on a screen 100 cm away from a 0.420-mm-wid
ID: 2253854 • Letter: H
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A diffraction pattern is formed on a screen 100 cm away from a 0.420-mm-wide slit. Monochromatic 546.1-nm light is used. Calculate the fractional intensity J//max at a point on the screen 4.10 mm from the center of the principal maximum. The pupil of a cat's eye narrows to a vertical slit of width 0.510 mm in daylight. Assume the average wavelength of the light is 573 nm. What is the angular resolution for horizontally separated mice? (In this problem, you may use the Rayleigh criterion for the limiting angle of resolution of an eye.)Explanation / Answer
gIven
L=1m
Y=4.1mm =4.1*10-3m
d=0.4mm =0.42*10-3m
?=546.1nm =546.1*10-9m
sin? =Y/L =4.1*10-3/1 =4.1*10-3
? =?dsin?/?
=?*0.42*10-3*4.1*10-3/546.1*10-9
? =9.901 radians
I/Io =[sin(?)/?]2
=[sin(9.901*180/?)/9.901]2
=21.855*10-4
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