Just need the answers for A and B. Thanks! In the figure below(Figure 1), the to

Question

Just need the answers for A and B. Thanks!

In the figure below(Figure 1), the top left capacitor and top right capacitor has 2.3muF , the middle capacitor has 3.7muF , and the bottom capacitor has 7.1muF , and the voltage across ab is 49V. Calculate the charge on each capacitor. Enter your answer as four numbers correspoding to the four charges, separated with commas. Give in the order Ctop left, Ctop right, Cmiddle, Cbottom Calculate the potential difference across each capacitor. Enter your answer as four numbers correspoding to four potential differencies, separated with commas. Give in the order Ctop left, Ctop right, Cmiddle, Cbottom

Explanation / Answer

A) the potential difference across C2 and C1 will be the same.so,

4.01*10^-5/(2.82*10^-6)=q/(7.29*10^-6)

or q=1.03*10^-4 C

b) charge on C3=1.03*10^-4+4.01*10^-5

=1.431*10^-4 C

c) Vab=4.01*10^-5/(2.82*10^-6) + 1.431*10^-4/(4.73*10^-6

=44.47 V

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