help please, be specific with equations A block of mass 5.00 kg is placed agains
ID: 2253997 • Letter: H
Question
help please, be specific with equations
A block of mass 5.00 kg is placed against a compressed spring at the bottom of a ramp. The ramp is inclined at 36.9° above the horizontal. The coefficient of kinetic friction between the block mid the ramp is mu k = 0.400. The spring is released and it gives up all of its stored energy to the block. The block travels a distance 3.00 m along the ramp before momentarily coming to rest. During the motion of the block up the ramp, how much work is done on it by the friction force? How much elastic potential energy was initially stored in the spring?Explanation / Answer
friction = mu*mg*cos(theta)
W(fric.) = F.s = -mu*mg*d*cos(theta)
-0.4*5*9.81*3*c0s(36.9) = -47.02 J
B)
W(total) = mghsin(36.9) - Wf
= b)mghsin(36.9) + 47.02
= 135.281 J
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