1.A man of mass 84.9 kg and density 970. kg / m 3 stands in a shallow pool with

Question

1.A man of mass 84.9kg and density 970.kg/m3 stands in a shallow pool with 36.3% of the volume of his body below water. Calculate the normal force the bottom of the pool exerts on his feet.

2.A very large balloon with mass M=13.3kg is inflated to a volume of

23.7m3 using a gas of density ?gas=0.205kg/m3. What is the maximum mass m that can be tied to the balloon using a 2.19kg piece of rope without the balloon falling to the ground? (Assume that the density of air is 1.30kg/m3 and that the volume of the gas is equal to the volume of the inflated balloon).

Explanation / Answer

1. bayoyant force= Volume of body in water * density of water * g

= (84.9/970 * .363) * 1000 * 9.8

= 311.36 N

normal force = its wieght - bayoyant force

= 84.9 * 9.8 - 311.36

= 520.6 N

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