Only full detailed answers with all the parts solved will be rated. A point char
ID: 2254446 • Letter: O
Question
Only full detailed answers with all the parts solved will be rated.
A point charge of 2.00- mu C is located at (0.00, 0.500, 0.00) m What is the electric potential of the 2.00-mu C charge at (0.00, -50.0, 0.00) m? (17.2) If a point charge of 6.00- mu C is located at (0.00, -0.500, 0.00) m, what is the electric potential energy stored in this system? (17.1) If a point charge of 6.00-muC is located at (0.00, -0.500, 0.00) m and then released, what will the kinetic energy of this particle be when the particle is a great distance from the origin? (17.6) If a point charge of 6.00-mu C is located at (0.00, -0.500, 0.00) m and then released, what is the change that the electric potential will have passed through due to the 2.00-mu C charge (assuming this charge to be fixed) when the kinetic energy of the 6.00-mu C particle is 0.400 J? (17.3, 17.4)Explanation / Answer
a) potential = KQ/R = (9*10^9)*(2*10^-6)/(50+0.5) = 356.436 V
b)potential = KQ/R = (9*10^9)*(2*10^-6)/(0.5+0.5) = 18000 V
potential energy = potential * charge = 18000*6*10^-6 = 0.108 J
c)at great distance all potential energy will be convereted to kinetic energy, as at great distance potential energy will be zero.
so,
kinetic energy = 0.108 J
d)change in potential energy = 0.4 J
so,
change in potential = change in potential energy/charge = 0.4/(6*10^-6) = 66666.67 V
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