1st Answer is correct however the second answer is wrong. Make sure to convert t

Question

1st Answer is correct however the second answer is wrong.

Make sure to convert to feet for final answer.

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Although gas station owners lock their tanks at night, a gas station owner in your neighborhood was the victim of theft because his employee had a key to the tank. The owner of the gas station wants to bury the gasoline so deep that no vacuump pump, no matter how powerful, will be able to extract it. He has hired you as a general contractor to dig the holes for the tanks. What is the minimum depth needed for the surface of the gasoline to be unsiphonable? Assume the specific gravity of gasoline is 0.755. (You can ignore the drop rate of the gasoline level inside the tank.) The gas station owner balks at your estimate. He neither has the funds nor approval from the city to dig that deeply. However, you tell him that the best a thief could hope to have at his disposal is a 194-mbar vacuum pump. Anything better would be enormously expensive. Given this information, how deep would the gasoline have to sit below the surface to keep it safe from thieves?

Explanation / Answer

the atmospheric pressure is 1000mbar, the vaccum pump generates a pressure of 194 mbar.

so the difference in pressures = 806mbar.

lets say the depth of the hole is X metres.

the pressure applied by X m high gasoline would be = density*height*gravity = 755*X*10 = 7550X pa

this pressure is equal to the difference in presures = 806 mbar = 80600 pa

=> 7550X = 80600

=> X= 80600/7550 m

=> X = 35.5 ft

the depth required is approximately 35.5 ft

(the answer may be + or - 0.5 ft due to the variations in atmospheric pressure taken)

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