Two identical rollers are mounted with their axes parallel, in a horizontal plan
ID: 2255172 • Letter: T
Question
Two identical rollers are mounted with their axes parallel, in a horizontal plane, a distance 2d=49.6 cm apart. The two rollers are rotating inwardly at the top with the same angular speed ?. A long uniform board is laid across them in a direction perpendicular to their axes. The board of mass m=3.52 kg is originally placed so that its center of mass lies a distance x0=10 cm from the point midway between the rollers. The coefficient of friction between the board and rollers is ?k=0.653. What is the period of the motion?
Two identical rollers are mounted with their axes parallel, in a horizontal plane, a distance 2d=49.6 cm apart. The two rollers are rotating inwardly at the top with the same angular speed ?. A long uniform board is laid across them in a direction perpendicular to their axes. The board of mass m=3.52 kg is originally placed so that its center of mass lies a distance x0=10 cm from the point midway between the rollers. The coefficient of friction between the board and rollers is ?k=0.653. What is the period of the motion?Explanation / Answer
anything in motion has an effect on the proximate continuum so id say that the period of motion is defined by whatever coordinates best reflect the cyclical nature of the motion.
From some perspective either temporal, spatial, harmonic, distropic, or other dimensionally defined coordinate will see all motion as cyclical in being, and from that coordinate I think is where you'll find your needed definition for the period of motion
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