%3Cp%3EThe%20frequency%26nbsp%3Band%26nbsp%3Bwavelength%26nbsp%3Bof%26nbsp%3Ba%2

Question

%3Cp%3EThe%20frequency%26nbsp%3Band%26nbsp%3Bwavelength%26nbsp%3Bof%26nbsp%3Ba%26nbsp%3Btransverse%26nbsp%3Bwave%26nbsp%3Bon%26nbsp%3Ba%26nbsp%3Bstring%26nbsp%3Bare%26nbsp%3B340%26nbsp%3BHz%0A%26nbsp%3Band%26nbsp%3B0.70%26nbsp%3Bm%2C%26nbsp%3Brespectively.%26nbsp%3BThe%26nbsp%3Btension%26nbsp%3Bin%26nbsp%3Bthe%26nbsp%3Bstring%26nbsp%3Bis%26nbsp%3B160%26nbsp%3BN.%26nbsp%3BWhat%26nbsp%3Bis%26nbsp%3B%0Athe%26nbsp%3Blinear%0A%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3Bdensity%26nbsp%3Bof%26nbsp%3Bthe%26nbsp%3Bstring%26nbsp%3Bin%26nbsp%3Bkilograms%3F%0A%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%26nbsp%3B%3C%2Fp%3E

Explanation / Answer

velocity = sqrt ( tension / mass per unit length )

f1 = velocity / 2L

velocity = 340 * 1.4 = 476

velocity ^2 = tension / mass per unit length

226576 * mass per unit length = 160

mass per unit length = 160 / 226576 = 7.0616x10^-4 kg /m

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.