The hammer throw is a track-and-field event in which a 7.0-kg ball (the \'\'hamm
ID: 2255446 • Letter: T
Question
The hammer throw is a track-and-field event in which a 7.0-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 23.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 414 m/s. Determine the work done to launch the motion of both the hammer and the bullet.
The hammer throw is a track-and-field event in which a 7.0-kg ball (the ''hammer''), starting from rest, is whirled around in a circle several times and released. It then moves upward on the familiar curving path of projectile motion. In one throw, the hammer is given a speed of 23.0 m/s. For comparison, a .22 caliber bullet has a mass of 2.6 g and, starting from rest, exits the barrel of a gun with a speed of 414 m/s. Determine the work done to launch the motion of both the hammer and the bullet. the hammer the bulletExplanation / Answer
The centripetal force is M*Vo^2/R
R = 1.60 m in this case. The path of the hammer is an inclined circle with that radius.
You need to know the speed at release, Vo.
You can get Vo from the distance of the world recrod throw, using
86.75 m = (Vo^2/g)*sin(2*35.9)
Vo = 29.9 m/s
Now solve for the centripetal force.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.