Please show all work A police officer is chasing a burglar across a rooftop. The

Question

Please show all work

A police officer is chasing a burglar across a rooftop. The burglar is running at 4.5 m/s when he jumps horizontally, trying desperately to reach the next roof which is 6.2 m away but 4.8m lower.

a) How much time does the burglar spend in free-fall as he falls through the vertical distance of 4.8m?

b) What horizontal distance does the burglar travel during the time he falls 4.8m vertically?

c) The police officer wishes to avoid the tragic fate of the burglar. If she also jumps horizontally from one building to the next, what must be her minimum initial speed?

Explanation / Answer

a)

as he jumps horizontally

he has no initial vertical speed

and vertical displacement is 4.8m

so

H=ut-.5gt^2

u=H=4.8 , g=9.8

so

t=sqrt(2H/g)=sqrt(2*4.8/9.8)=0.98974 sec

horizontal distance =time*speed=0.98974*4.5=4.45383 m

time taken by police officer is also same=.98974sec

so,

its min speed should be

V*.98974=6.2

V=6.2/(0.98974)=6.2642 m/s

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