In the figure, point P 1 is at distance R = 11.2 cm on the perpendicular bisecto

Question

In the figure, point P1 is at distance R = 11.2 cm on the perpendicular bisector of a straight wire of length L = 16.7 cm carrying current i = 68.1 mA. (Note that the wire is not long.) What is the magnitude of the magnetic field at P1 due to i (in T)?

In the figure, point P1 is at distance R = 11.2 cm on the perpendicular bisector of a straight wire of length L = 16.7 cm carrying current i = 68.1 mA. (Note that the wire is not long.) What is the magnitude of the magnetic field at P1 due to i (in T)?

Explanation / Answer

B = [mue*i/(4*pi*r)]*(sin(theta1) + sin(theta2))

here theta1 = theta2

theta1 = tan^-1(R /(L/2))

= tan^-1(11.2/(16.7/2))

= 53.3 degrees


B = [mue*i/(4*pi*R)] * (2*sin(theta1))

= [4*pi*10^-7*68.1/(4*pi*0.112)] *2*sin(53.3)

= 9.75*10^-5 T

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.