divers at a shipwreck in the caribbean wants to lift a 15 gold bricks to the sur

Question

divers at a shipwreck in the caribbean wants to lift a 15 gold bricks to the surface with some tethered inflated balloons.the balloons have a diameter of 1 foot . one gold brick is a rectangular solid measuring 9 in by 5 inch by 2 inch. in the calculation ignore the mass of balloon and air inside and the mass of the tether lines.The density of gold is 19.3 times 10^3 kg/m3 and the seawater is 1.03 times 10^3 kg/m^3.

A,what is the minimum number of balloons necessary to cause the gold brick to float upward.

B,if the number of balloon in part a is used what will the acceleration of the brick be upward

Explanation / Answer

Volume of 1 brick = 9*5*2 = 90 in31.4748*10^-3 m3

Total mass = Total vol * density = 15*V*19.3*10^3 = 427 kg

Volume of 1 baloon, Vb = pi*d^3/6 = 1.482*10^-2 m3

For lifting, Buoyancy = Force of gravity

n*Vb *density of water *g = mg

n = m/(Vb*density of water) = 27.97

So, number of baloons used = 28.

B net = 28*Vb*1.03*10^3 * 9.8 = 4188.606 N

F = mg = 427*9.8 = 4184.6

acc. = (B-F)/m = 9.38*10^-3 m/s2

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.