Problem 30.28 In an experimental radiation therapy, an equivalent dose of 0.500
ID: 2256508 • Letter: P
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Problem 30.28 In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Problem 30.28 In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Problem 30.28 In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. Problem 30.28 In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part A What is the absorbed dose, in rad? D = 0.100 rad Correct D = 0.100 rad D = 0.100 rad 0.100 Correct Correct Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining N = N = Try Again; 9 attempts remaining Try Again; 9 attempts remaining Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N = N = N = Problem 30.28 In an experimental radiation therapy, an equivalent dose of 0.500rem is given to a localized area of tissue with a mass of 0.170kg by 0.800MeVprotons. Part A What is the absorbed dose, in rad? D = 0.100 rad Correct Part B How many protons are absorbed by the tissue? N = Try Again; 9 attempts remaining Part C How many alpha particles of the same energy of 0.800MeV are required to deliver the same equivalent dose of 0.500rem ? N =Explanation / Answer
Please check the calculations
equivalent dose = 0.500 rem
mass of the tissue m = 0.17 kg
energy of the proton E = 0.8 MeV = 0.8*106 eV
RBE for protons = 5
...........................................................
absorbed dose = equivalent dose / RBE
= (0.5rem)/ (5 rem/rad)
= 0.1 rad
................................................................
absorbed dose = equivalent dose / RBE
= 0.5 rem / (5 Sv/Gy)
= 10*10-4 Gy (1 Gy = 1 J/kg)
= 10*10-4 J/kg
total energy abosorbed is
E' = (0.17 kg)(10*10-4 J/kg)
= 1.3*10-4 J
= (1.3*10-4 J)(1 eV / 1.6*10-19 J)
= 8.125*1014 eV
number of protons are absorbed by the tissue is
N = (8.125*1014 eV) / (0.8*106 eV)
= 10.15*108 protons
...........................................................................
RBE for ? - particles = 20 rem/rad
energy of ? - particles = 0.8 MeV = 0.8*106 eV
absorbed dose = equivalent dose / RBE
= (0.5 rem) / (20 rem / rad)
= (0.5*0.01 Sv) / (20 Sv/Gy)
= 2.5*10-4 Gy
= 2.5*10-4 J/kg
energy abosorbed is
E'' = (0.17 kg)(2.5*10-4 J/kg)
= 3.25*10-5 J
= (3.25*10-5 J)(1 eV / 1.6*10-19 J)
= 2.03*1014 eV
number of ? - particles = (2.03*1014 eV) / (0.8*106 eV)
= 2.54*108
= 0.254*109
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