(A) A wire of mass m = 11 grams and length L = 69 cm is suspended by a pair of f

Question

(A) A wire of mass m = 11 grams and length L = 69 cm is suspended by a pair of flexible leads in a uniform magnetic field B = 0.65 T as shown in the figure. What is the magnitude of the current (in mA) if there is no tension in the flexible leads?  NOTE: 1 mA = 10?3A and g = 9.8 m/s2

(B) What is the direction of the current in this case?

                                             
A- depends on the magnetic force
B- from right to left         
C- cannot be determined         
D- from left to right

A wire of mass m = 11 grams and length L = 69 cm is suspended by a pair of flexible leads in a uniform magnetic field B = 0.65 T as shown in the figure. What is the magnitude of the current (in mA) if there is no tension in the flexible leads? What is the direction of the current in this case? depends on the magnetic force from right to left cannot be determined from left to right

Explanation / Answer

(A.) If there's a current in the wire, it experience a force I( L x B )

This force should be equal to the weight of wire for 0 tension...

weight = mg = 11*10^-3 * 9.8 = 0.1078N = I * L * B

I = 0.1078 / (0.69 * 0.65) = 0.24 A

(B.) to counter mg, the force I (L xB) should be upward in direction..

where L has a direction of direction of current...

you can see that for L -> left to right (right hand rule), the force will be in upward direction to counter the weight..

so, asnwer = left to right

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