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Only full detailed answer will be rated Compared to a 30.0 Ohm resistor another

ID: 2256541 • Letter: O

Question

Only full detailed answer will be rated

Compared to a 30.0 Ohm resistor another resistor made from the same material has twice (2 00X) the cross sectional area, but half (0 500x) the length. If this second resistor is connected in a series with a 12.0 V battery, what is the current in this circuit? (20.4) In a circuit, a 24.0-V battery is in series with a 4.00-Ohm resistor and an unknown resistor. (All three are in one unbranching current loop.) If there is an 8.00-V drop over the 4.00-Ohm resistor, what is the resistance of the second resistor? (20.7)

Explanation / Answer

1) When S1 is opened and S2 is closed, we will have a capacitor discharging from the resistor R2


The bulb will glow for some time and then turn off as the current value decreases from maximum to minimum.


2) V = Vo ( 1 - e^(-t/RC) )


RC = 300 * 0.002 = 0.6 sec

Vo = 15 V


So, voltage across capacitor after t = 5.0 sec = Vo(1 - e^(-5 / 0.6) ) = 14.99 V i.e approx 15 V


Thus, it is almost completely charged.


Now, when S2 is on and S1 is off,

RC = 600 * 0.002 = 1.2 sec

Thus, while discharging,

V = Vo ( e^ (-t/RC) )


Thus at t = 4.0 sec


V = 15 (e^(-4/1.2)) = 0.535 V is the potential difference


Charge = CV = 0.002 * 0.535 = 1.07 * 10^-3 coloums = 1.07mC



3) the third part is a bit ambiguous one. At what instant does it want the switch #1 to be closed.

What is the condition of switch #2 at that time.


considering switch S2 open:

power dissipated = v^2 / R = 15^2 / 300 = 225 / 300 = 0.75W


Please let me know if you have any doubts and I shall try to help you out over here. Hope this helps. Thanks.


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