1. A ball is launched horizontally from a table that is 1.8m tall. If the ball h

ID: 2256599 • Letter: 1

Question

1. A ball is launched horizontally from a table that is 1.8m tall. If the ball has an initial velocity of 14 m/s determine:

a. the time it takes for the ball to hit the ground

b. how far it will land from the table

c. the balls final velocity in the y direction

2. A civil war era cannon is capable of firing a cannonball at 150 m/s. If it is set to fire at 39 degrees above the horizontal:

a. how long will it stay in the air

b. how far will it go horizontally

c. what is the maximum height the cannonball will reach

Consider g =10m/s^2

a)Time taken to hit the ground = sqrt(2H/g)

This doesn't depend on the Horizontal velocity as this velocity is perpendicular to the vertical velocity

==> T = sqrt(2*1.8/10) = sqrt(0.36) = 0.6sec

b)Distance from the table = ut

= 14 * 0.6 m

distance from the table = 8.4m

c)Final velocity in y-direction Vy= Uy + gt

==> Vy = 0 + 10 * 0.6

==>Vy = 6m/sec

2)Ux = 150 cos(39)m/sec

Uy = 150 sin(39) m/sec

a)Time = 2*Uy /g = (150sin(39))*2/10 = 30sin(39) sec

b)Horizontal range = Ux * Time = 150 cos(39) * 30 sin(39)= 2250 *2sin(39)cos(39) =2250sin(78)m

c)Maximum height = Uy^2 /2g = (150sin(39))^2/2*10 = 1125(sin(39))^2 m

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