A torque is applied to a long thin rod making it rotate with an angular accelera

Question

A torque is applied to a long thin rod making it rotate with an angular acceleration of 6.95 rad/s2 about an axis through its center and perpendicular to its length (see the Figure (a) below). If the same torque is now applied to make the rod rotate about an axis about one end perpendicular to its length (see Figure (b) below), determine the new angular acceleration of the rod.
rad/s2

A torque is applied to a long thin rod making it rotate with an angular acceleration of 6.95 rad/s2 about an axis through its center and perpendicular to its length (see the Figure (a) below). If the same torque is now applied to make the rod rotate about an axis about one end perpendicular to its length (see Figure (b) below), determine the new angular acceleration of the rod.

Explanation / Answer

As we know that

Torque = I*alpha = Constant

Inew =(1/3)mL^2

Iold = (1/12)ml^2

As I becomes 4 time

Therefore

w becomes 1/4 times

= 6.95/4

= 1.7375 rad/sec^2

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