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You are trying to overhear a juicy conversation, but from your distance of 21.0

ID: 2256760 • Letter: Y

Question


  You are trying to overhear a juicy conversation, but from your distance of 21.0m , it sounds like only an average whisper of 25.0dB . So you decide to move closer to give the conversation a sound level of 75.0dB  instead. Part A How close should you come? d =
cm SubmitMy AnswersGive Up Try Again
  You are trying to overhear a juicy conversation, but from your distance of 21.0m , it sounds like only an average whisper of 25.0dB . So you decide to move closer to give the conversation a sound level of 75.0dB  instead.
  You are trying to overhear a juicy conversation, but from your distance of 21.0m , it sounds like only an average whisper of 25.0dB . So you decide to move closer to give the conversation a sound level of 75.0dB  instead.   You are trying to overhear a juicy conversation, but from your distance of 21.0m , it sounds like only an average whisper of 25.0dB . So you decide to move closer to give the conversation a sound level of 75.0dB  instead.   You are trying to overhear a juicy conversation, but from your distance of 21.0m , it sounds like only an average whisper of 25.0dB . So you decide to move closer to give the conversation a sound level of 75.0dB  instead. Part A How close should you come? d =
cm SubmitMy AnswersGive Up Try Again Part A How close should you come? d =
cm SubmitMy AnswersGive Up Try Again Part A How close should you come? d =
cm SubmitMy AnswersGive Up Try Again Part A How close should you come? d =
cm SubmitMy AnswersGive Up Try Again Part A How close should you come? d =
cm SubmitMy AnswersGive Up Try Again d =
cm d =
cm SubmitMy AnswersGive Up Try Again Try Again Try Again d =
cm

Explanation / Answer

I1/I2=10^(dB1/10)/10^(dB2/10)

I1/I2=10^(25/10)/10^(75/10)=10^-5

Intensity is inversely proportional to distance squared, so

I1/I2=d2^2/d1^2

d2=(I1/I2)^0.5*d1

d2=(10^-5)^0.5*21

d2 =0.066 m= 6.6 cm

You should come to 6.6 cm

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