An Atwood Machine consists of two blocks m 1 = 15 kg and m 2 = 23 kg connected b
ID: 2257020 • Letter: A
Question
An Atwood Machine consists of two blocks m1 = 15 kg and m2 = 23 kg connected by a massless string that passes over a pulley in the shape of a pulley which has a mass of 5 kg and a radius of 0.25 m. What is the acceleration of the blocks and the tension in each part of the string when the system is released? What is the normal force on the pin supporting the pulley? An Atwood Machine consists of two blocks m1 = 15 kg and m2 = 23 kg connected by a massless string that passes over a pulley in the shape of a pulley which has a mass of 5 kg and a radius of 0.25 m. What is the acceleration of the blocks and the tension in each part of the string when the system is released? What is the normal force on the pin supporting the pulley?Explanation / Answer
For Tension 2:
g=9.8m/s^2
m2(9.8)-T2=m2(a)
** 23(9.8)-T2=23*(a)
For Tension 1:
T1-m1(9.8)=m1(a)
** T1-15(9.8)=15*(a)
For solid cylinder:
r=radius
I=moment of inertia
alpha=angular acceleration
a=acceleration
rT2-T1= I*alpha
I=.5mr^2
alpha=a/r
r(T2-T1)= .5mr^2(a/r)
radius cancels out leaving:
T2-T1=.5(mass of cylinder)a=
** T2-T1=.5(5.0)= 2.5*(a)
By adding all the equations
23*g - 15 *g - 2.5*a = 38*a
8*9.8 =40.5*a
a = 1.9358
T1 = 15*1.93.28 + 15*9.8
T1 = 176.037
T2 =23*1.9358 + 23 *9.8
T2 = 269.9234
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