two billiard balls collide as shown in the figure below. Ball 1 is initially tra

Question

two billiard balls collide as shown in the figure below. Ball 1 is initially traveling along x with a speed of 20 m/s, and ball 2 is at rest. After the collision, ball 1 moves away with a speed of 4.8 m/s at an angle ? = 56

two billiard balls collide as shown in the figure below. Ball 1 is initially traveling along x with a speed of 20 m/s, and ball 2 is at rest. After the collision, ball 1 moves away with a speed of 4.8 m/s at an angle ? = 56degree. Find the speed of ball 2 after the collision. What angle does the final velocity of ball 2 make with the x axis?

Explanation / Answer

along y-direction.-- conserving momentum

4.8*sin 56 + v2_y = 0

so.. v_y = - 3.97938 m/sec

along x-direction.. conserving momentum

20 = 4.8*cos 56 + v2_x
so.. v2_x = 17.3159 m/sec

so. a) speed of ball 2 = sqrt( 3.97938^2 + 17.3159^2) = 17.7673 m/sec


b) angle = tan inverse ( vy / vx ) = tan inverse ( - 3.97938/17.3159) = -12.9425 dgree

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